# 01. The LinearOpeator¶

This first tutorial is aimed at easing the use of the PyLops library for both new users and developers.

Since PyLops heavily relies on the use of the scipy.sparse.linalg.LinearOperator class of SciPy, we will start by looking at how to initialize a linear operator as well as different ways to apply the forward and adjoint operations. Finally we will investigate various special methods, also called magic methods (i.e., methods with the double underscores at the beginning and the end) that have been implemented for such a class and will allow summing, subtractring, chaining, etc. multiple operators in very easy and expressive way.

Let’s start by defining a simple operator that applies element-wise multiplication of the model with a vector d in forward mode and element-wise multiplication of the data with the same vector d in adjoint mode. This operator is present in PyLops under the name of pylops.Diagonal and its implementation is discussed in more details in the Implementing new operators page.

import timeit

import matplotlib.pyplot as plt
import numpy as np

import pylops

n = 10
d = np.arange(n) + 1.0
x = np.ones(n)
Dop = pylops.Diagonal(d)


First of all we apply the operator in the forward mode. This can be done in four different ways:

• _matvec: directly applies the method implemented for forward mode
• matvec: performs some checks before and after applying _matvec
• *: operator used to map the special method __matmul__ which checks whether the input x is a vector or matrix and applies _matvec or _matmul accordingly.
• @: operator used to map the special method __mul__ which performs like the * opetator

We will time these 4 different executions and see how using _matvec (or matvec) will result in the faster computation. It is thus advised to use * (or @) in examples when expressivity has priority but prefer _matvec (or matvec) for efficient implementations.

# setup command
cmd_setup = """\
import numpy as np
import pylops
n = 10
d = np.arange(n) + 1.
x = np.ones(n)
Dop = pylops.Diagonal(d)
DopH = Dop.H
"""

# _matvec
cmd1 = "Dop._matvec(x)"

# matvec
cmd2 = "Dop.matvec(x)"

# @
cmd3 = "Dop@x"

# *
cmd4 = "Dop*x"

# timing
t1 = 1.0e3 * np.array(timeit.repeat(cmd1, setup=cmd_setup, number=500, repeat=5))
t2 = 1.0e3 * np.array(timeit.repeat(cmd2, setup=cmd_setup, number=500, repeat=5))
t3 = 1.0e3 * np.array(timeit.repeat(cmd3, setup=cmd_setup, number=500, repeat=5))
t4 = 1.0e3 * np.array(timeit.repeat(cmd4, setup=cmd_setup, number=500, repeat=5))

plt.figure(figsize=(7, 2))
plt.plot(t1, "k", label=" _matvec")
plt.plot(t2, "r", label="matvec")
plt.plot(t3, "g", label="@")
plt.plot(t4, "b", label="*")
plt.axis("tight")
plt.legend()


Out:

<matplotlib.legend.Legend object at 0x7f90d0ce0ac8>


Similarly we now consider the adjoint mode. This can be done in three different ways:

• _rmatvec: directly applies the method implemented for adjoint mode
• rmatvec: performs some checks before and after applying _rmatvec
• .H*: first applies the adjoint .H which creates a new scipy.sparse.linalg._CustomLinearOperator where _matvec and _rmatvec are swapped and then applies the new _matvec.

Once again, after timing these 3 different executions we can see see how using _rmatvec (or rmatvec) will result in the faster computation while .H* is very unefficient and slow. Note that if the adjoint has to be applied multiple times it is at least advised to create the adjoint operator by applying .H only once upfront. Not surprisingly, the linear solvers in scipy as well as in PyLops actually use matvec and rmatvec when dealing with linear operators.

# _rmatvec
cmd1 = "Dop._rmatvec(x)"

# rmatvec
cmd2 = "Dop.rmatvec(x)"

# .H* (pre-computed H)
cmd3 = "DopH*x"

# .H*
cmd4 = "Dop.H*x"

# timing
t1 = 1.0e3 * np.array(timeit.repeat(cmd1, setup=cmd_setup, number=500, repeat=5))
t2 = 1.0e3 * np.array(timeit.repeat(cmd2, setup=cmd_setup, number=500, repeat=5))
t3 = 1.0e3 * np.array(timeit.repeat(cmd3, setup=cmd_setup, number=500, repeat=5))
t4 = 1.0e3 * np.array(timeit.repeat(cmd4, setup=cmd_setup, number=500, repeat=5))

plt.figure(figsize=(7, 2))
plt.plot(t1, "k", label=" _rmatvec")
plt.plot(t2, "r", label="rmatvec")
plt.plot(t3, "g", label=".H* (pre-computed H)")
plt.plot(t4, "b", label=".H*")
plt.axis("tight")
plt.legend()


Out:

<matplotlib.legend.Legend object at 0x7f90d124c9e8>


Just to reiterate once again, it is advised to call matvec and rmatvec unless PyLops linear operators are used for teaching purposes.

We now go through some other methods and special methods that are implemented in scipy.sparse.linalg.LinearOperator (and pylops.LinearOperator):

• Op1+Op2: maps the special method __add__ and performs summation between two operators and returns a pylops.LinearOperator
• -Op: maps the special method __neg__ and performs negation of an operators and returns a pylops.LinearOperator
• Op1-Op2: maps the special method __sub__ and performs summation between two operators and returns a pylops.LinearOperator
• Op1**N: maps the special method __pow__ and performs exponentiation of an operator and returns a pylops.LinearOperator
• Op/y (and Op.div(y)): maps the special method __truediv__ and performs inversion of an operator
• Op.eigs(): estimates the eigenvalues of the operator
• Op.cond(): estimates the condition number of the operator
• Op.conj(): create complex conjugate operator
# +
print(Dop + Dop)

# -
print(-Dop)
print(Dop - 0.5 * Dop)

# **
print(Dop ** 3)

# * and /
y = Dop * x
print(Dop / y)

# eigs
print(Dop.eigs(neigs=3))

# cond
print(Dop.cond())

# conj
print(Dop.conj())


Out:

<10x10 LinearOperator with dtype=float64>
<10x10 LinearOperator with dtype=float64>
<10x10 LinearOperator with dtype=float64>
<10x10 LinearOperator with dtype=float64>
[1. 1. 1. 1. 1. 1. 1. 1. 1. 1.]
[10.+0.j  9.+0.j  8.+0.j]
(9.999999999999986+0j)
<10x10 _ConjLinearOperator with dtype=float64>


To understand the effect of conj we need to look into a problem with an operator in the complex domain. Let’s create again our pylops.Diagonal operator but this time we populate it with complex numbers. We will see that the action of the operator and its complex conjugate is different even if the model is real.

n = 5
d = 1j * (np.arange(n) + 1.0)
x = np.ones(n)
Dop = pylops.Diagonal(d)

print("y = Dx = ", Dop * x)
print("y = conj(D)x = ", Dop.conj() * x)


Out:

y = Dx =  [0.+1.j 0.+2.j 0.+3.j 0.+4.j 0.+5.j]
y = conj(D)x =  [0.-1.j 0.-2.j 0.-3.j 0.-4.j 0.-5.j]


At this point, the concept of linear operator may sound abstract. The convinience method pylops.LinearOperator.todense can be used to create the equivalent dense matrix of any operator. In this case for example we expect to see a diagonal matrix with d values along the main diagonal

D = Dop.todense()

plt.figure(figsize=(5, 5))
plt.imshow(np.abs(D))
plt.title("Dense representation of Diagonal operator")
plt.axis("tight")
plt.colorbar()


Out:

<matplotlib.colorbar.Colorbar object at 0x7f90d14eabe0>


Finally it is worth reiterating that if two linear operators are combined by means of the algebraical operations shown above, the resulting operator is still a pylops.LinearOperator operator. This means that we can still apply any of the methods implemented in the original scipy class definition like *, as well as those in our class definition like /

Dop1 = Dop - Dop.conj()

y = Dop1 * x
print("x = (Dop - conj(Dop))/y = ", Dop1 / y)

D1 = Dop1.todense()

plt.figure(figsize=(5, 5))
plt.imshow(np.abs(D1))
plt.title(r"Dense representation of $|D + D^*|$")
plt.axis("tight")
plt.colorbar()


Out:

x = (Dop - conj(Dop))/y =  [1.+0.j 1.+0.j 1.+0.j 1.+0.j 1.+0.j]

<matplotlib.colorbar.Colorbar object at 0x7f90cd1d7f60>


This first tutorial is completed. You have seen the basic operations that can be performed using scipy.sparse.linalg.LinearOperator and our overload of such a class pylops.LinearOperator` and you should be able to get started combining various PyLops operators and solving your own inverse problems.

Total running time of the script: ( 0 minutes 0.630 seconds)

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